Answer
$-\dfrac{3}{5}$
Work Step by Step
$\sin{x} = - \sqrt{1-\left(\dfrac{1}{\sqrt{10}}\right)^2} = - \dfrac{3\sqrt{10}}{10}$
$\sin{2x} = 2 \sin{x} \cos{x} = 2 \times - \dfrac{3\sqrt{10}}{10} \times \dfrac{1}{\sqrt{10}}$
$\sin{2x} = - \dfrac{3}{5}$
