Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - 4.7 Problem Set - Page 261: 23

Answer

$\frac{3\pi}{4}$

Work Step by Step

$\cos^{-1}(-\frac{\sqrt 2}{2})= \cos^{-1}(-\frac{1}{\sqrt 2})$. Let $\cos^{-1}(-\frac{1}{\sqrt 2})=y$. Then, cos y= $-\frac{1}{\sqrt 2}= -cos(\frac{\pi}{4})= \cos(\pi-\frac{\pi}{4})= \cos \frac{3\pi}{4}$. Therefore, y= $\frac{3\pi}{4}$.
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