Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - 4.7 Problem Set - Page 261: 17

Answer

$\frac{\pi}{3}$

Work Step by Step

Let $\sin^{-1}(\frac{\sqrt 3}{2})=y$. Then, sin y= $\frac{\sqrt 3}{2}$. We know that $\sin(\frac{\pi}{3})= \frac{\sqrt 3}{2}$. Therefore y=$\frac{\pi}{3}$.
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