Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 2 - Section 2.5 - Vectors: A Geometric Approach - 2.5 Problem Set - Page 107: 34


1800 ft

Work Step by Step

Magnitude of the horizontal component of the velocity vector in problem 32 is $|\textbf{V}_{x}|=900\,ft/s$. Given that $t= 2\,s$. Horizontal distance=|$\textbf{V}_{x}$|$\times$time$=900\,ft/s\times2\,s=1800\,ft$
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