Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 2 - Section 2.5 - Vectors: A Geometric Approach - 2.5 Problem Set - Page 107: 36


$|\textbf{d}_{s}|=565\,km$ $|\textbf{d}_{w}|=396\,km$

Work Step by Step

Displacement $d=velocity\times time=230\,km/h(in\,the\,direction\,S\,35^{\circ}W)\times3\,h$$=690\,km$ in the direction S $35^{\circ}$ W. Magnitude of the component of the displacement vector along the south is given by $|\textbf{d}_{s}|=|\textbf{d}|\cos\theta=690\,km\times \cos 35^{\circ}=565\,km$ Distance travelled in the west direction is $|\textbf{d}_{w}|=|\textbf{d}|\sin35^{\circ}=690\,km\times\sin35^{\circ}=396\,km$
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