Answer
2550 ft
Work Step by Step
Magnitude of the horizontal component of the velocity vector in problem 31 is $|\textbf{V}_{x}|=850\,ft/s$. Given that $t= 3\,s$.
Horizontal distance=|$\textbf{V}_{x}$|$\times$time$=850\,ft/s\times3\,s=2550\,ft$