## Trigonometry 7th Edition

Chapter 2 - Section 2.3 Problem Set: 37 (Answer) Refer to Figure I $A = 50.12^{\circ}$ (To four significant digits) $B = 39.88^{\circ}$ (To four significant digits) $a = 451.6$ inches (To four significant digits)
Chapter 2 - Section 2.3 Problem Set: 37 (Solution) Refer to Figure I $\cos A = \frac{b}{c}$ $A = \cos^{-1} (\frac{377.3}{588.5})$ $A = 50.12^{\circ}$ (To four significant digits) $\sin B = \frac{b}{c}$ $B = \sin^{-1} (\frac{377.3}{588.5})$ $B = 39.88^{\circ}$ (To four significant digits) By Pythagoras' Theorem $a^2$ + $b^2$ = $c^2$ $a^2$ = $588.5^2$ - $377.3^2$ $a$ = $\sqrt{(588.5^2 - 377.3^2)}$ $a = 451.6$ inches (To four significant digits)