# Chapter 2 - Section 2.3 - Solving Right Triangles - 2.3 Problem Set - Page 80: 31

Chapter 2 - Section 2.3 Problem Set: 31 (Answer) Refer to Figure I $\angle A$ = $63^{\circ}30{}’=63.5^\circ$ $c = 726$ mm (To three significant digits) $a = 650$ mm (To three significant digits)

#### Work Step by Step

Chapter 2 - Section 2.3 Problem Set: 31 (Solution) Refer to Figure I $\angle A$ + $\angle B$ + $90^{\circ}$ = $180^{\circ}$ ($\angle$ sum of $\triangle$) $\angle A$ + $26.5^{\circ}$ + $90^{\circ}$ = $180^{\circ}$ ($26^{\circ}30{}'$ = $26\frac{30}{60}^{\circ}$ = $26.5^{\circ}$) $\angle A$ = $63.5^{\circ}$ = $63^{\circ}30{}’$ $\sin 26.5^{\circ} = \frac{b}{c}$ $c = \frac{324}{\sin 26.5^{\circ}}$ $c = 726$ mm (To three significant digits) $\tan 26.5^{\circ} = \frac{b}{a}$ $a = \frac{324}{\tan 26.5^{\circ}}$ $a = 650$ mm (To three significant digits)

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