Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 2 - Section 2.3 - Solving Right Triangles - 2.3 Problem Set - Page 80: 24

Answer

Chapter 2 - Section 2.3 Problem Set: 24 (Answer) Drawing : Refer to Figure I $\angle B$ = $49^{\circ}$ $a = 24$ m (To two significant digits) $b = 27$ m (To two significant digits)
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Work Step by Step

Chapter 2 - Section 2.3 Problem Set: 24 (Solution) Drawing : Refer to Figure I $\angle A$ + $\angle B$ + $90^{\circ}$ = $180^{\circ}$ ($\angle$ sum of $\triangle$) $41^{\circ}$ + $\angle B$ + $90^{\circ}$ = $180^{\circ}$ $\angle B$ = $49^{\circ}$ $\sin 41^{\circ} = \frac{a}{c}$ $a = 36 \cdot \sin 41^{\circ}$ $a = 24$ m (To two significant digits) $\cos 41^{\circ} = \frac{b}{c}$ $b = 36 \cdot \cos 41^{\circ}$ $b = 27$ m (To two significant digits)
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