Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 2 - Section 2.2 - Calculators and Trigonometric Functions of an Acute Angle - 2.2 Problem Set - Page 71: 29

Answer

$17.3^{\circ}$

Work Step by Step

To convert $17^{\circ} 20'$ to decimal degrees, let's break it as- $17^{\circ} 20'$ = $17^{\circ}$ + $20'$ Now on dividing $20'$ by 60, we have the number of "decimal degrees" equivalent to $20'$ (as $ 1^{\circ} = 60'$) Therefore $17^{\circ} 20'$ = $17^{\circ}$ + $(\frac{20}{60})^{\circ}$ $17^{\circ} 20'$ = $17^{\circ}$ + $0.333...^{\circ}$ $17^{\circ} 20'$ = $17^{\circ}$ + $0.3^{\circ}$ (Rounding to the nearest hundredth) $17^{\circ} 20'$= $17.3^{\circ}$
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