Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 2 - Section 2.2 - Calculators and Trigonometric Functions of an Acute Angle - 2.2 Problem Set - Page 71: 47


$\tan42^{\circ}15′$ = 0.9083

Work Step by Step

First we will convert $42^{\circ}15′$ to decimal degrees, let's break it as- $42^{\circ}15′$ = $42^{\circ}$ + $15′$ Now on dividing 15′ by 60, we have the number of "decimal degrees" equivalent to 15′ (as $1^{\circ}$=60′) Therefore $42^{\circ}15′$ = $42^{\circ} + (\frac{15}{60})^{\circ}$ $42^{\circ}15′$ = $42^{\circ} + 0.25^{\circ}$ $42^{\circ}15′$= $42.25^{\circ}$ Now Using calculator in degree mode- $\tan 42.25^{\circ}$ = 0.9083360465 Rounding it to four places past the decimal point- $\tan 42.25^{\circ}$ = 0.9083 Therefore- $\tan42^{\circ}15′$ = 0.9083
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.