## Trigonometry 7th Edition

Published by Cengage Learning

# Chapter 2 - Section 2.2 - Calculators and Trigonometric Functions of an Acute Angle - 2.2 Problem Set - Page 71: 14

#### Answer

$67^{\circ} 41'$

#### Work Step by Step

$180^{\circ}$ - ($112^{\circ} 19')$ $180^{\circ}$ can also be written as $179^{\circ} 60'$ ( converting 1 degree to 60 minutes) therefore the problem becomes- $179^{\circ} 60'$ - $112^{\circ}19'$ $179^{\circ} 60'$ - $112^{\circ} 19'$ ________ $67^{\circ} 41'$ Answer is $67^{\circ} 41'$

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