Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 1 - Section 1.3 - Definition I: Trigonometric Functions - 1.3 Problem Set - Page 32: 33

Answer

True

Work Step by Step

As can be seen from the figure: $$\sec{60^\circ} = \dfrac{r_1}{x}\,\,\, \&\,\,\,\, \sec{75^\circ} = \dfrac{r_2}{x}$$ $$r_1 = \sqrt{x^2+y_1^2} \,\,\,\,\,\&\,\,\,\,\,r_2 = \sqrt{x^2+y_2^2}$$ $$\because y_2 > y_1 \,\,\,\,\,\, \therefore r_2 > r_1$$ $\therefore \sec(75^{\circ}) > \sec(60^{\circ})$
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