## Trigonometry 7th Edition

$\cos{\theta} =0.8 \\\sin{\theta} =0.6$
(Assumption: the angle is in standard position) If the point $(9.36, 7.02)$ is on the terminal side of $\theta$. then $r$ can be solved using the formula: $r=\sqrt{x^2 + y^2}$ The given point has $x=9.36$ and $y=7.02$. Substitute these values into the formula above to obtain: $r= \sqrt{9.36^2 + 7.02^2} \\r = 11.7$ RECALL: $\sin{\theta} = \dfrac{y}{r} \\\cos{\theta} = \dfrac{x}{r}$ Use the formulas above and the known values of x, y, and r to obtain: $\cos{\theta} = \dfrac{936}{11.7}=0.8 \\\sin{\theta} = \dfrac{7.02}{11.7}=0.6$