Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 5 - Trigonometric Identities - Section 5.1 Fundamental Identities - 5.1 Exercises - Page 196: 88

Answer

The answer to Exercise 87 is the negative of $y=-sin{2x}$.

Work Step by Step

From Exercise 87, we got $y=\sin{(-2x)} = -\sin{2x}$, which means that $y=\sin{(-2x)}$ is equivalent to $y=-\sin{2x}$ Note that $-\sin{2x}$ is just the opposite (or negative or additive inverse) of $\sin{2x}$. Therefore, the answer in Exercise 87 is the negative of $y=-\sin{2x}$.
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