Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 4 - Review Exercises - Page 183: 6

Answer

The amplitude is 1. The period is $\frac{2\pi}{b}=\frac{2\pi}{3}$. There is no vertical translation as $c=0$. There is no phase shift as $d=0$.

Work Step by Step

We first write the equation in the form $y=c+a \tan [b(x-d)]$. Therefore, $y=\tan (3x)$ becomes $y=0+1\tan [3(x-0)]$. Comparing the two equations, $a=1,b=3,c=0$ and $d=0$. The amplitude is $|a|=|1|=1.$ The period is $\frac{2\pi}{b}=\frac{2\pi}{3}$. There is no vertical translation as $c=0$. There is no phase shift as $d=0$.
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