Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 4 - Review Exercises - Page 183: 14

Answer

The amplitude is $2$ The period is $2$ The vertical translation is 0 The phase shift is $2$

Work Step by Step

$y = A~sec(Bx+C)+D$ $y = 2~sec(\pi x-2\pi)$ $A = 2$ $B = \pi$ $C = -2\pi$ $D = 0$ $\vert A \vert$ is the amplitude. The amplitude is $2$ $\frac{2\pi}{B}$ is the period. The period is $2$ $D$ is the vertical translation. The vertical translation is 0 $\frac{-C}{B}$ is the phase shift. The phase shift is $2$
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