Answer
The amplitude is $1$
The period is $4\pi$
The vertical translation is 0
The phase shift is $-\frac{3\pi}{2}$
Work Step by Step
$y = A~tan(Bx+C)+D$
$y = cot(\frac{x}{2}+\frac{3\pi}{4})$
$A = 1$
$B = \frac{1}{2}$
$C = \frac{3\pi}{4}$
$D = 0$
$\vert A \vert$ is the amplitude.
The amplitude is $1$
$\frac{2\pi}{B}$ is the period.
The period is $4\pi$
$D$ is the vertical translation.
The vertical translation is 0
$\frac{-C}{B}$ is the phase shift.
The phase shift is $-\frac{3\pi}{2}$
