Answer
The amplitude is $|a|=|2|=2.$
The period is $\frac{2\pi}{b}=\frac{2\pi}{1}=2\pi$.
There is no vertical translation as $c=0$.
There is no phase shift as $d=0$.
Work Step by Step
We first write the equation in the form $y=c+a \sin [b(x-d)]$. Therefore, $y=2\sin (x)$ becomes $y=0+2\sin [1(x-0)]$.
Comparing the two equations, $a=2,b=1,c=0$ and $d=0$.
The amplitude is $|a|=|2|=2.$
The period is $\frac{2\pi}{b}=\frac{2\pi}{1}=2\pi$.
There is no vertical translation as $c=0$.
There is no phase shift as $d=0$.
