Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 3 - Radian Measure and the Unit Circle - Section 3.4 Linear and Angular Speed - 3.4 Exercises - Page 125: 40d

Answer

The linear speed at Salem is $1185~km/hr$

Work Step by Step

The earth rotates through an angle of $2\pi$ radians in 24 hours. We can find the angular speed: $\omega = \frac{2\pi~rad}{24~hrs}$ $\omega = \frac{\pi~rad}{12~hrs}$ $\omega = 0.2618~rad/hr$ The angular speed is $0.2618~rad/hr$ At a point halfway between the equator and the North Pole, we can find the radius of rotation $r$: $\frac{r}{6400~km} = sin ~45^{\circ}$ $r = (6400~km) (sin ~45^{\circ})$ $r = 4525~km$ We can find the linear speed at Salem: $v = \omega ~r$ $v = (0.2618~rad/hr)(4525~km)$ $v = 1185~km/hr$ The linear speed at Salem is $1185~km/hr$
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