Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 3 - Radian Measure and the Unit Circle - Section 3.4 Linear and Angular Speed - 3.4 Exercises: 31

Answer

$v = 0.012~cm/s$

Work Step by Step

The minute hand of a clock moves through an angle of $2\pi$ radians in a time of 3600 seconds. We can find the angular speed: $\omega = \frac{\theta}{t}$ $\omega = \frac{2\pi~rad}{3600~s}$ $\omega = \frac{\pi}{1800}~rad/s$ We can find the linear speed: $v = \omega ~r$ $v = (\frac{\pi}{1800}~rad/s)(7~cm)$ $v = 0.012~cm/s$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.