#### Answer

$\omega = \frac{\pi}{30}~rad/s$ which is $0.105~rad/s$

#### Work Step by Step

The second hand of a clock moves through $2\pi$ radians in a time of 60 seconds. We can find the angular speed:
$\omega = \frac{\theta}{t}$
$\omega = \frac{2\pi~rad}{60~s}$
$\omega = \frac{\pi}{30}~rad/s$
$\omega = 0.105~rad/s$