Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.4 Solving Right Triangles - 2.4 Exercises - Page 73: 28

Answer

$\angle A = 51^{\circ}$ $\angle B= 39^{\circ}$ $a =40 ft$

Work Step by Step

1. $c = 51ft$ and $b =32 ft$ 2. $\angle B = \sin^{-1} \frac{32}{51} = 38.9^{\circ}$ 3. $\cos 38.9^{\circ} =\frac{a}{51}$ $a \approx 39.7ft$ 4. $\angle A = 180^{\circ} -90^{\circ} -38.9 ^{\circ} = 51.1^{\circ}$ 5. Answers in 2 significant figures as given values $\angle A= 51^{\circ}$ and $\angle B = 39^{\circ}$ and $a = 40ft$
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