Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.4 Solving Right Triangles - 2.4 Exercises: 14

Answer

$\angle A= 21.4858^{\circ}$ $b \approx 3330.68 m$ $a \approx 1311.04 m$

Work Step by Step

1. $\angle B = 68.5142^{\circ}$ $c= 3579.42 m$ 2. $\angle B +\angle A = 90^{\circ}$ $\angle A = 21.4858^{\circ}$ 3. $\sin B = \frac{b}{c}$ $b= 3579.42 \times \sin (68.5142^{\circ}) \approx 3330.68 m$ 4. $\cos B = \frac{a}{c}$ $a= 3579.42 \times \cos (68.5142^{\circ}) \approx 1311.04 m$
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