## Trigonometry (10th Edition)

$b \approx 58.2 km$ $\angle B = 58^{\circ} 20'$ $c \approx 68.4 km$
1. $\angle B = 90^{\circ} -31^{\circ} 40' = 58^{\circ}20'$ 2. $\tan 31^{\circ} 40' = \frac{35.9}{b}$ $b= 35.9 \tan 31^{\circ} 40'\approx 58.2 km$ 3.$\sin 31^{\circ} 40' =\frac{35.9}{c}$ $c = 35.9 \sin 31^{\circ} 40' \approx 68.4km$