Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 1 - Trigonometric Functions - Section 1.3 Trigonometric Functions - 1.3 Exercises - Page 26: 51

Answer

$\sin\theta=\frac{y}{r}=\frac{-1}{\sqrt {2}}=\frac{-\sqrt {2}}{2}$ $\cos\theta=\frac{x}{r}=\frac{1}{\sqrt {2}}=\frac{\sqrt {2}}{2}$ $\tan\theta=\frac{y}{x}=\frac{-1}{1}=-1$ $\csc\theta=\frac{1}{\sin\theta}=\frac{\sqrt {2}}{-1}=-\sqrt 2$ $\sec\theta=\frac{1}{\cos\theta}=\frac{\sqrt {2}}{1}=\sqrt 2$ $\cot\theta=\frac{1}{\tan\theta}=\frac{1}{-1}=-1$

Work Step by Step

$x=1$ $y=-1$ $r=\sqrt {(1)^{2}+(-1)^{2}}=\sqrt {1+1}=\sqrt {2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.