Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 1 - Trigonometric Functions - Section 1.3 Trigonometric Functions - 1.3 Exercises - Page 26: 2

Answer

$\sin\theta = \frac{y}{r} = \frac{-5}{13}$ $\cos\theta = \frac{x}{r} = \frac{-12}{13}$ $\tan\theta = \frac{y}{x} = \frac{-5}{-12}$ $\csc\theta = \frac{r}{y} = \frac{13}{-5}$ $\sec\theta = \frac{r}{x} = \frac{13}{-12}$ $\cot\theta = \frac{x}{y} = \frac{-12}{-5}$

Work Step by Step

$x = -12$ $y = -5$ $r = \sqrt {(-5)^2 + (-12)^2}$ $r = \sqrt {25 + 144}$ $r = 13$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.