Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 1 - Trigonometric Functions - Section 1.3 Trigonometric Functions - 1.3 Exercises - Page 26: 19

Answer

$\sin\theta=\frac{y}{r}=\frac{-2}{4}=-\frac{1}{2}$ $\cos\theta=\frac{x}{r}=\frac{-2\sqrt 3}{4}=-\frac{\sqrt 3}{2}$ $\tan\theta=\frac{y}{x}=\frac{-2}{-2\sqrt3}=\frac{\sqrt 3}{3}$ $\csc\theta=\frac{r}{y}=\frac{4}{-2}=-2$ $\sec\theta=\frac{r}{x}=\frac{4}{-2\sqrt 3}=-\frac{2\sqrt 3}{3}$ $\cot\theta=\frac{x}{y}=\frac{-2\sqrt 3}{-2}=\sqrt 3$

Work Step by Step

$x=-2\sqrt 3$ $y=-2$ $r=\sqrt{(-2)^{2}+(-2\sqrt 3)^{2}}=\sqrt {4+12}= 4$
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