## Trigonometry (10th Edition)

The solution is {$\frac{-2 \pm \sqrt{10}}{2}$}
$0.2x^2$ $+ 0.4x$ $- 0.3$ = $0$ $2x^2$ $+ 4x$ $- 3$ = $0$ $x$ $=$ $\frac{-4 \pm \sqrt{4^2 - (4)(2)(-3)}}{2 (2)}$ (Quadratic formula) $x$ $=$ $\frac{-4 \pm \sqrt{16 + 24}}{4}$ $x$ $=$ $\frac{-4 \pm 2\sqrt{10}}{4}$ $x$ $=$ $\frac{-2 \pm \sqrt{10}}{2}$ The solution is {$\frac{-2 \pm \sqrt{10}}{2}$}