Answer
{$-\frac{5}{6}$}
Work Step by Step
$36x^{2}+60x+25=0$
$36x^{2}+30x+30x+25=0$
$6x(6x+5)+5(6x+5)=0$
$(6x+5)(6x+5)=0$
$(6x+5)=0$ or $(6x+5)=0$
$x=-\frac{5}{6}$ or $x=-\frac{5}{6}$
Check:
Substituting $x=-\frac{5}{6}$ in the equation,
$36(-\frac{5}{6})^{2}+60(-\frac{5}{6})+25=0$
$\frac{36\times25}{36}-\frac{60\times5}{6}+25=0$
$25-50+25=0$
$0=0$
The value checks and the solution set is {$-\frac{5}{6}$}
