Answer
{$\pm4$}
Work Step by Step
According to the square root property,
if $x^{2}=16$
then $x=\sqrt (16)=4$ or $x=-\sqrt (16)=-4$
Therefore, the solution set is{$-4,+4$} or {$\pm4$}
Trigonometry (10th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
0321671775
ISBN 13:
978-0-32167-177-6
Appendix A - Equations and Inequalities - Page 417: 45
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