Answer
$x=±4i\sqrt 3$
Work Step by Step
$x^{2}+48=0$
$x^{2}=-48$
$x=±\sqrt -48$
$x=±(\sqrt 16\times\sqrt 3\times\sqrt -1)$
$x=±4i\sqrt 3$
We know that $\sqrt 16=4$, because $4^{2}=16$.
We know that $\sqrt -1=i$, because $-1^{2}=i$.
Trigonometry (11th Edition) Clone
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
978-0-13-421743-7
ISBN 13:
978-0-13421-743-7
Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.1 Complex Numbers - 8.1 Exercises - Page 364: 88
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