## Trigonometry (11th Edition) Clone

$x=±4i\sqrt 3$
$x^{2}+48=0$ $x^{2}=-48$ $x=±\sqrt -48$ $x=±(\sqrt 16\times\sqrt 3\times\sqrt -1)$ $x=±4i\sqrt 3$ We know that $\sqrt 16=4$, because $4^{2}=16$. We know that $\sqrt -1=i$, because $-1^{2}=i$.