Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.1 Complex Numbers - 8.1 Exercises - Page 364: 85



Work Step by Step

$x^{2}=-16$ $x=±\sqrt -16$ $x=±(\sqrt 16\times\sqrt -1)$ $x=±4i$ We know that $\sqrt 16=4$, because $4^{2}=16$. We know that $\sqrt -1=i$, because $-1^{2}=i$.
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