#### Answer

$x=±4i$

#### Work Step by Step

$x^{2}=-16$
$x=±\sqrt -16$
$x=±(\sqrt 16\times\sqrt -1)$
$x=±4i$
We know that $\sqrt 16=4$, because $4^{2}=16$.
We know that $\sqrt -1=i$, because $-1^{2}=i$.

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Published by
Pearson

ISBN 10:
978-0-13-421743-7

ISBN 13:
978-0-13421-743-7

$x=±4i$

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