## Trigonometry (11th Edition) Clone

$1$ sq. unit
We first use the formula $A=\frac{1}{2}bh$ to find the area of the triangle: $A=\frac{1}{2}bh$ $A=\frac{1}{2}(1)(2)$ $A=\frac{2}{2}$ $A=1$ Now, we use the formula $Area=\frac{1}{2}ab \sin C$ to verify the result: $Area=\frac{1}{2}ab \sin C$ $Area=\frac{1}{2}(\sqrt 2)(2) \sin 45$ $Area=\frac{2\sqrt 2}{2} \sin 45$ $Area=\sqrt 2(\sin45)$ $Area=\sqrt 2(\frac{\sqrt 2}{2})$ $Area=\frac{\sqrt 2\times\sqrt 2}{2}$ $Area=\frac{2}{2}$ $Area=1$ Therefore, both the formulas give the same area which is $1$ sq. unit.