#### Answer

$\frac{\sqrt 3}{2}$ sq. units

#### Work Step by Step

We first use the formula $A=\frac{1}{2}bh$ to find the area of the triangle:
$A=\frac{1}{2}bh$
$A=\frac{1}{2}(1)(\sqrt 3)$
$A=\frac{\sqrt 3}{2}$
Now, we use the formula $Area=\frac{1}{2}ab \sin C$ to verify the result:
$Area=\frac{1}{2}ab \sin C$
$Area=\frac{1}{2}(1)(\sqrt 3) \sin 90$
$Area=\frac{\sqrt 3}{2} \sin 90$
$Area=\frac{\sqrt 3}{2}(1)$
$Area=\frac{\sqrt 3}{2}$
Therefore, both the formulas give the same area which is $\frac{\sqrt 3}{2}$ sq. units.