#### Answer

$\sqrt 3$ sq. units

#### Work Step by Step

We first use the formula $A=\frac{1}{2}bh$ to find the area of the triangle:
$A=\frac{1}{2}bh$
$A=\frac{1}{2}(2)(\sqrt 3)$
$A=\sqrt 3$
Now, we use the formula $Area=\frac{1}{2}ab \sin C$ to verify the result:
$Area=\frac{1}{2}ab \sin C$
$Area=\frac{1}{2}(2)(2) \sin 60$
$Area=\frac{4}{2} \sin 60$
$Area=2(\sin60)$
$Area=2(\frac{\sqrt 3}{2})$
$Area=\sqrt 3$
Therefore, both the formulas give the same area which is $\sqrt 3$ sq. units.