Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Review Exercises - Page 292: 64


$\theta_1 = 48.76^{\circ}$

Work Step by Step

$\frac{c_1}{c_2} = \frac{sin~\theta_1}{sin~\theta_2}$ If $\theta_2 = 90^{\circ}$, then $sin~\theta_2 = 1$ We can find the value of $\theta_1$: $\frac{c_1}{c_2} = \frac{sin~\theta_1}{sin~\theta_2}$ $0.752 = \frac{sin~\theta_1}{1}$ $\theta_1 = arcsin(0.752)$ $\theta_1 = 48.76^{\circ}$
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