Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Review Exercises - Page 292: 57



Work Step by Step

Use a calculator to fund the value of $arctan{(1)}$ to obtain: $\arccos{(x)}+\frac{\pi}{4}=\frac{11\pi}{12} \\\arccos{(x)}=\frac{11\pi}{12}-\frac{\pi}{4} \\\arccos{(x)}=\frac{2\pi}{3}$ RECALL: $\arccos{(x)}=\theta \longrightarrow \cos{\theta} = x$ Use the rule above to obtain: $\arccos{(x)}=\frac{2\pi}{3} \\\cos{(\frac{2\pi}{3})}=x \\-\frac{1}{2}=x$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.