Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Review Exercises - Page 292: 62


$t = \frac{50}{\pi}~arccos(\frac{d-550}{450})$

Work Step by Step

$d = 550+450~cos(\frac{\pi}{50}~t)$ $450~cos(\frac{\pi}{50}~t) = d-550$ $cos(\frac{\pi}{50}~t) = \frac{d-550}{450}$ $\frac{\pi}{50}~t = arccos(\frac{d-550}{450})$ $t = \frac{50}{\pi}~arccos(\frac{d-550}{450})$
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