## Trigonometry (11th Edition) Clone

$x=\frac{3}{5}$
Given: $arcsinx=arctan\frac{3}{4}$ Consider $arctan\frac{3}{4}=P$ $tan P=\frac{3}{4}$ Apply trigonometric identity for tangent. $tanx=\frac{opp}{adj}=\frac{3}{4}$ Thus, $hyp=\sqrt {3^{2}+4^{2}}$ Likewise, $sinP=\frac{opp}{hyp}=\frac{3}{5}$ $arcsinx=P$ gives $x=sinP$ Hence, $x=\frac{3}{5}$