## Trigonometry (11th Edition) Clone

$1$
Given: $4\pi+4tan^{-1}(x)=\pi$ $4tan^{-1}(x)=-3 \pi$ $tan^{-1}(x)=(-\frac{3 \pi}{4})$ (Divide by 4) $x=tan(-\frac{3 \pi}{4})$ Apply definition of arctangent. $x=1$ Hence, $x=1$