Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Inverse Circular Functions and Trigonometric Equations - Section 6.4 Equations Involving Inverse Trigonometric Functions - 6.4 Exercises - Page 286: 28


$x=-\frac{\sqrt 3}{ 2}$

Work Step by Step

Given: $6$ $arccos$ $x=5\pi$ $arccosx=\frac{5\pi}{6}$ (Divide by 6) Apply definition of arccosine. $x=cos(\frac{5\pi}{6})$ Hence, $x=-\frac{\sqrt 3}{ 2}$
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