Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Inverse Circular Functions and Trigonometric Equations - Section 6.3 Trigonometric Equations II - 6.3 Exercises - Page 280: 57a

Answer

We can see a sketch of the graph in the viewing window $[0,0.03]$ by $[-0.005, 0.005]$
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Work Step by Step

$P = 0.003~sin~220~\pi~t+\frac{0.003}{3}~sin~660~\pi~t+\frac{0.003}{5}~sin~1100~\pi~t+\frac{0.003}{7}~sin~1540~\pi~t$ We can see a sketch of the graph in the viewing window $[0,0.03]$ by $[-0.005, 0.005]$
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