Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Inverse Circular Functions and Trigonometric Equations - Section 6.3 Trigonometric Equations II - 6.3 Exercises - Page 280: 57a

Answer

We can see a sketch of the graph in the viewing window $[0,0.03]$ by $[-0.005, 0.005]$

Work Step by Step

$P = 0.003~sin~220~\pi~t+\frac{0.003}{3}~sin~660~\pi~t+\frac{0.003}{5}~sin~1100~\pi~t+\frac{0.003}{7}~sin~1540~\pi~t$ We can see a sketch of the graph in the viewing window $[0,0.03]$ by $[-0.005, 0.005]$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.