## Trigonometry (11th Edition) Clone

$x = 1.28$
$2sin~2x-x^3+1 = 0$ $2sin~2x = x^3-1$ We can graph the two equations $~~y = 2sin~2x~~$ and $~~y = x^3-1~~$ to find the points of intersection. The blue graph is $~~y = x^3-1~~$ The red graph is $~~y = 2sin~2x~~$ On the interval $[0,2\pi]$, we can see that the point of intersection occurs when $~~x = 1.28~~$ The solution over the given interval is: $x = 1.28$