Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Inverse Circular Functions and Trigonometric Equations - Section 6.3 Trigonometric Equations II - 6.3 Exercises - Page 280: 55


$x = 1.28$

Work Step by Step

$2sin~2x-x^3+1 = 0$ $2sin~2x = x^3-1$ We can graph the two equations $~~y = 2sin~2x~~$ and $~~y = x^3-1~~$ to find the points of intersection. The blue graph is $~~y = x^3-1~~$ The red graph is $~~y = 2sin~2x~~$ On the interval $[0,2\pi]$, we can see that the point of intersection occurs when $~~x = 1.28~~$ The solution over the given interval is: $x = 1.28$
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