Trigonometry (11th Edition) Clone

$x = 0.692$ $x = 2.082$
$3cos~\frac{x}{2}+\sqrt{x}-2 = -\frac{x}{2}+2$ We can graph the two equations $~~y = 3cos~\frac{x}{2}+\sqrt{x}-2 ~~$ and $~~y = -\frac{x}{2}+2~~$ to find the points of intersection. The blue graph is $~~y = -\frac{x}{2}+2~~$ The red graph is $~~y = 3cos~\frac{x}{2}+\sqrt{x}-2 ~~$ On the interval $[0,2\pi]$, we can see that the points of intersection occur when $~~x = 0.692~~$ and $~~x = 2.082$ The solution over the given interval is: $x = 0.692$ $x = 2.082$