Trigonometry (11th Edition) Clone

$\frac{1}{16}~sin~59^{\circ}$
We can use this identity: $sin~2x = 2~sin~x~cos~x$ $\frac{1}{8}~sin~29.5^{\circ}~cos~29.5^{\circ}$ $= \frac{1}{16}~(2~sin~29.5^{\circ}~cos~29.5^{\circ})$ $= \frac{1}{16}~sin~59^{\circ}$