Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 4 - Graphs of the Circular Functions - Section 4.5 Harmonic Motion - 4.5 Exercises - Page 185: 7b

Answer

$3.46$ units

Work Step by Step

To determine the position at $t=1.25$, we need to substitute $t=1.25$ into the equation and solve: $s(t)=-4\cos\frac{2\pi}{3}t$ $s(t)=-4\cos(\frac{2\pi}{3}\times1.25)$ $s(t)=-4\cos(\frac{2\pi}{3}\times1.25)$ $s(t)=-4\cos(2.618)$ $s(t)=-4(-\frac{\sqrt 3}{2})$ $s(t)=2\sqrt 3=3.46$ units
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.