## Trigonometry (11th Edition) Clone

Published by Pearson

# Chapter 4 - Graphs of the Circular Functions - Section 4.5 Harmonic Motion - 4.5 Exercises - Page 185: 12c

#### Answer

Period$=\frac{1}{4}$ seconds frequency=4 oscillations per second

#### Work Step by Step

The period can be found by first comparing the equation $s(t)=-4\cos 8\pi t$ to $s(t)=a\cos w t$ to find $w$ which is the angular velocity. By comparing the two equations, we find that $w=8\pi$. Next, we find the period using the formula: Period$=\frac{2\pi}{w}$ Period$=\frac{2\pi}{8\pi}$ Period$=\frac{1}{4}$ seconds. Since frequency is the reciprocal of the period, it is 4 oscillations per second.

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