Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 4 - Graphs of the Circular Functions - Section 4.5 Harmonic Motion - 4.5 Exercises - Page 185: 14


$L=0.81$ ft

Work Step by Step

To find the length of the pendulum, we need to substitute the value of period $P=1$ sec in the formula and solve: $P=2\pi\sqrt {\frac{L}{32}}$ $1=2\pi\sqrt {\frac{L}{32}}$ $\frac{1}{2\pi}=\sqrt {\frac{L}{32}}$ $\frac{1}{4\pi^{2}}= {\frac{L}{32}}$ $\frac{32}{4\pi^{2}}= L$ $L=0.81$ ft
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