## Trigonometry (11th Edition) Clone

The horizontal blue dashed line is parallel to the ground. The transversal leaves congruent alternate angles, meaning that the angle the blue diagonal makes with the ground is also (label it with A) $A=29.5^{o}$ The height of the tower (label it with a) is a leg of a right triangle, opposite to the angle $A=29.5^{o}$ The side b = 36.0 m is adjacent to A. (SOHCAHTOA) We use $\displaystyle \tan A=\frac{a}{b}$ and solve for a: $a=b\cdot\tan A$ $=36.0\cdot\tan 29.5^{o}\approx$20.3678200148$\approx$20.4 m